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xpath获取当前标签的兄弟节点,父节点
xpath获取节点源码
指定对象下查找
xpath获取节点源码
资源编号:550730
热度:104
xpath获取节点源码
``` from lxml import etree detail="
111
" html = etree.HTML(detail) article = html.xpath('//article')[0] detail = etree.tostring(article, encoding='utf-8').decode('utf-8') print(detail) ```